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How can we calculate time period of electron in any  Bohr’s orbit?
5 years ago bharat bajaj
IIT Delhi
122 Points

Time period is calculated by total distance covered divided by velocity
Distance covered = Circumference = 2pi.r
where r = radius of bohr orbit
v = velocity of electron in orbit
Hence, T = 2pi.r/v
Thanks
Bharat Bajaj
5 years ago

T=2.pi.r/v
v=2.16x10^6m/s
r=0.529xn^2/z angstroms
T=(2.pi.0.529x10^-10xn^2/z)/2.16x10^6m/s
5 years ago
Time taken =2πr/ velocity                       2×3.14×0.529×10^-10 divided                by                        2.188×10^6 Time taken to complete 1 revolution by electron in 1 st orbit of hydrogen atom= 1.52×10^-16 seconds

2 years ago

T=(4€²n³h³)/Z²me⁴ .
OR
T=1.52*10^-16n³/Z²

For any orbit
For H atom n=1, Z=1

So it's value is T=1.52e-16 sec
8 months ago
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