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`        How can we calculate time period of electron in any  Bohr’s orbit?`
5 years ago

bharat bajaj
IIT Delhi
122 Points
```							Time period is calculated by total distance covered divided by velocityDistance covered = Circumference = 2pi.rwhere r = radius of bohr orbitv = velocity of electron in orbitHence, T = 2pi.r/vThanksBharat Bajajaskiitians faculty
```
5 years ago
pramod Gopinath
25 Points
```							T=2.pi.r/vv=2.16x10^6m/sr=0.529xn^2/z angstromsT=(2.pi.0.529x10^-10xn^2/z)/2.16x10^6m/s
```
5 years ago
Tanmay walekar
11 Points
```							Time taken =2πr/ velocity                       2×3.14×0.529×10^-10 divided                by                        2.188×10^6 Time taken to complete 1 revolution by electron in 1 st orbit of hydrogen atom= 1.52×10^-16 seconds
```
2 years ago
User
15 Points
```							T=(4€²n³h³)/Z²me⁴ .  ORT=1.52*10^-16n³/Z²  For any orbitFor H atom n=1, Z=1 So it's value is T=1.52e-16 sec
```
8 months ago
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