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How can three resistors of resistances 2 Ω, 3 Ω, and 6 Ω be connected to give a total resistance of1 Ω,

Pawan Prajapati , 3 Years ago
Grade 12
anser 1 Answers
Harshit Singh

Last Activity: 3 Years ago

Dear Student

R1 = 2 ohm
R2 = 3 ohm
R3 = 6 ohm
When R1,R2, R3 are connected in parallel we get
1/R = 1/R1 + 1/R2 + 1/R3
= 1/2 + 1/3 + 1/6
= 1 ohm.

Thanks

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