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How can grams of kcl are present in 4.3 ×10^24 solve this problem??

Asma , 6 Years ago
Grade 9
anser 1 Answers
Khimraj

Last Activity: 6 Years ago

mole of KCl = 4.3*1024/6.022140857 × 1023
 = 7.14 mole
in gram = 7.14*74.55 = 532.31 gm
Hope it clears......................

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