Henry’s law constant for CO 2 in water is 1.67 X

Question

Henry’s law constant for CO2 in water is 1.67 X 108 Pa at 298 K. Calculate the quantity of CO2 in 500 ml of soda water when packed under 2.5 atm CO2 pressure at 298 K.

Arun · Accepted Answer

According to Henry's law, pCO2 = KHxHere x is the mole fraction of carbon dioxide in the carbon dioxide water mixture.pCO2 = 2.5 atm = 2.5 * 1.01325 * 105 Pa = 2.533125 * 105 Pax = mole fraction = 2.533125 * 105/ 1.67 * 108 = 0.00152x = moles of CO2/(moles of CO2 + moles of H2O) ≈moles of CO2/moles of H2Oas mole of CO2are negligible in comparison to the number of moles of water500 ml of water = 500g of water = 500/18 = 27.78 moles of water.So, moles of CO2/27.78 = 0.00152 or moles of CO2 = 0.042 moles. Hence the amount of CO2 in 500 ml of soda water is 0.042 * 44 = 1.848 g RegardsArun (askIITians forum expert)

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Physical Chemistry> Henry’s law constant for CO 2 in water is...

Henry’s law constant for CO2 in water is 1.67 X 108 Pa at 298 K. Calculate the quantity of CO2 in 500 ml of soda water when packed under 2.5 atm CO2 pressure at 298 K.

Aiden Mathew Denny , 6 Years ago

Arun

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