he electronic transitions from n = 2 to n = 1 will produce shortest wavelength in (where n = principal quantum state)
(A) Li+2
(B) He+
(C) H
(D) H+
saurabh kumar
12 Years agoGrade 12
2 Answers
nandan
9 Years ago
since the orbits for transition are the same, the wavelength will only depend on the atomic number. So wavelength is directly proportional to the square of the atomic number. So the shortest wavelength is of H (h+ has no electrons).
Ritik kushwah
7 Years ago
Answer is Li^2+ because lembda is inversely proportional to z^2 here li^2+ has maximum z therefore it's wavelength is minimum