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he electronic transitions from n = 2 to n = 1 will produce shortest wavelength in (where n = principal quantum state) (A) Li+2 (B) He+ (C) H (D) H+

he electronic transitions from n = 2 to n = 1 will produce shortest wavelength in (where n = principal quantum state)
(A) Li+2
(B) He+
(C) H
(D) H+

Grade:12

2 Answers

nandan
13 Points
4 years ago
since the orbits for transition are the same, the wavelength will only depend on the atomic number. 
So wavelength is directly proportional to the square of the atomic number. So the shortest wavelength is of H (h+ has no electrons).
 
Ritik kushwah
15 Points
3 years ago
Answer is Li^2+ because  lembda is inversely proportional to z^2  here li^2+ has maximum z therefore it's wavelength is minimum
 
 
 
 

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