he electronic transitions from n = 2 to n = 1 will produce shortest wavelength in (where n = principal quantum state)
(A) Li+2
(B) He+
(C) H
(D) H+
saurabh kumar , 12 Years ago
Grade 12
2 Answers
nandan
since the orbits for transition are the same, the wavelength will only depend on the atomic number. So wavelength is directly proportional to the square of the atomic number. So the shortest wavelength is of H (h+ has no electrons).
Last Activity: 8 Years ago
Ritik kushwah
Answer is Li^2+ because lembda is inversely proportional to z^2 here li^2+ has maximum z therefore it's wavelength is minimum
Last Activity: 7 Years ago
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