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Grade 11Physical Chemistry

Give one chemical test to distinguish between the following pairs of compounds. (i) Methylamine and dimethylamine (ii) Secondary and tertiary amines (iii) Ethylamine and aniline (iv) Aniline and benzylamine (v) Aniline and N-methylaniline

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12 Years agoGrade 11
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ApprovedApproved Tutor Answer1 Year ago

To differentiate between the pairs of compounds you've listed, we can use specific chemical tests that exploit the unique properties of each compound. Let's go through each pair one by one, highlighting a suitable test for each.

Methylamine and Dimethylamine

To distinguish between methylamine and dimethylamine, we can use the ninhydrin test. Both compounds will react with ninhydrin, but the intensity of the color change will differ. Methylamine, being a primary amine, will produce a blue color, while dimethylamine, a secondary amine, will yield a less intense color. This difference arises because primary amines react more vigorously with ninhydrin than secondary amines.

Secondary and Tertiary Amines

For identifying secondary amines versus tertiary amines, the nitrous acid test is effective. When a secondary amine is treated with nitrous acid, it forms a diazonium salt, which can be further hydrolyzed to produce an alcohol. In contrast, tertiary amines do not react with nitrous acid and will remain unchanged. This distinction is due to the lack of a hydrogen atom attached to the nitrogen in tertiary amines, preventing the formation of the diazonium salt.

Ethylamine and Aniline

To differentiate between ethylamine and aniline, we can utilize the Hinsberg test. When treated with benzene sulfonyl chloride, ethylamine (a primary amine) will form a soluble sulfonamide, while aniline (a primary aromatic amine) will form an insoluble sulfonamide. The solubility difference allows us to distinguish between these two compounds effectively.

Aniline and Benzylamine

The solubility test in hydrochloric acid can be employed here. Aniline, being an aromatic amine, is less soluble in dilute hydrochloric acid compared to benzylamine, which is an aliphatic amine. When you add hydrochloric acid, benzylamine will dissolve readily, while aniline will not dissolve as well, allowing for clear differentiation.

Aniline and N-Methylaniline

To tell apart aniline from N-methylaniline, we can use the acetylation test. When both compounds are treated with acetic anhydride, aniline will form a solid acetanilide, while N-methylaniline will produce a liquid product due to steric hindrance. The physical state of the products provides a straightforward way to distinguish between the two amines.

These tests leverage the unique chemical properties of the amines in question, allowing for clear differentiation based on their reactivity and solubility characteristics. Understanding these differences is crucial in organic chemistry, especially when working with various amine compounds.