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for the reactions, n205........>2no2+1/2o2 given -d[n205]/dt=k1[n2o5], d[no2]/dt=k2[n2o5] ,d[o2]/dt=k3[n2o5] the relation between k1, k2, k3 is
From the concepts of chemcial kinetcs we know,-d(n205)/dt = (+1/2)d(no2)/dt = (+2)d(o2)/dtand given -d[n205]/dt=k1[n2o5], d[no2]/dt=k2[n2o5] ,d[o2]/dt=k3[n2o5] .Now put the values,we get,k1[n2o5] = 0.5k2[n2o5]k1 = 0.5k2and(+1/2)k2[n2o5] = (+2)k3[n2o5] .k2 = 4k3Thus,k1/k2 = (0.5/4)(k2/k3)k1*k3 = (k2^2)/8is the final relation.
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