For the reaction at 25°C, N2O4(g) = 2NO2(g) if delGf° for N2O4 and NO2 are 23.49 and 12.39 kcal respectively then Ko for the reaction is(in atm)...Ans is 0.1132atm
Adeel , 6 Years ago
Grade 12th pass
1 Answers
Arun
Last Activity: 4 Years ago
Let, 1 mol of N
2
O
4
present initially.
N
2
O
4
⇋2NO
2
t=0: 1 0
t=t
eq
: 1−x 2x
So, the number of molecules at equilibrium =n
N
2
O
4
+n
NO
2
=1+x−2x=1+x.
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