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Grade 12Physical Chemistry

For the reaction A---->B rate constant is k1 which is equal to x perhrs. and for reaction A----->C rate constant is k2. given ; k1:k2 = 1:10. Calculate [C]/[A] after one hour from the start of the reaction. Assuming only A was present in the beginning.

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10 Years agoGrade 12
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To solve the problem of calculating the ratio of concentrations [C]/[A] after one hour for the given reactions, we need to analyze the kinetics of both reactions. We have two reactions involving the same reactant A, converting it into products B and C with different rate constants.

Understanding the Rate Constants

We know that the rate constants for the reactions are related as follows:

  • For the reaction A → B, the rate constant is k1 = x per hour.
  • For the reaction A → C, the rate constant is k2 = 10x per hour (since k1:k2 = 1:10).

Setting Up the Differential Equations

Since both reactions occur simultaneously, we can express the change in concentration of A over time using the following differential equation:

Let [A] be the concentration of A at time t. The rate of change of [A] can be described by:

d[A]/dt = -k1[A] - k2[A]

Substituting the values of k1 and k2, we get:

d[A]/dt = -x[A] - 10x[A] = -11x[A]

Solving the Differential Equation

This is a first-order linear differential equation. We can separate variables and integrate:

∫(1/[A]) d[A] = -11x ∫dt

Integrating both sides gives us:

ln[A] = -11xt + C

Exponentiating both sides results in:

[A] = e^C * e^(-11xt)

At time t = 0, let’s denote the initial concentration of A as [A]₀. Thus, we can express C as:

[A] = [A]₀ * e^(-11xt)

Calculating Concentrations of B and C

Next, we need to find the concentrations of B and C after one hour (t = 1). The concentration of B can be determined using the integrated rate law for a first-order reaction:

[B] = [A]₀ - [A]

Substituting for [A]:

[B] = [A]₀ - [A]₀ * e^(-11x)

[B] = [A]₀(1 - e^(-11x))

For the concentration of C, we use the same approach:

[C] = [A]₀ - [A] - [B]

[C] = [A]₀ - [A]₀ * e^(-11x) - [A]₀(1 - e^(-11x))

[C] = [A]₀ * e^(-11x)

Finding the Ratio [C]/[A]

Now, we can calculate the ratio of [C] to [A] after one hour:

[C]/[A] = ([A]₀ * e^(-11x)) / ([A]₀ * e^(-11x)) = 1

Thus, after one hour, the ratio of the concentrations of C to A is:

[C]/[A] = 1

Final Thoughts

This result indicates that the concentration of C is equal to the concentration of A after one hour, given the specified rate constants and initial conditions. This type of analysis is fundamental in chemical kinetics, allowing us to predict the behavior of reactants and products over time.