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For the reaction A+B->product The rate of the reaction was doubled when concentration of A was double. When concentration A and B was doubled then again rate was doubled find the order of reaction. With respect to A and B.

For the reaction A+B->product The rate of the reaction was doubled when concentration of A was double. When concentration A and B was doubled then again rate was doubled find the order of reaction. With respect to A and B.

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1 Answers

Norman Manchu
151 Points
6 years ago
When A was doubled rate was doubled thus-
\frac{R}{2R}=\frac{k(A)^{a}(B)}{k(2A)^{a}(B)}
Hence 2^a=2
a=order of A=1
Rate doubled when A and B both were doubled which signifies that there was no effect of change in B thus b=order of B=0
 
 
Answer should be 1and0
Order of reaction=1+0=1
 
 
 
 
 
 
 

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