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For the following equilibrium, Kc= 6.3 × 1014 at 1000 K NO (g) + O3 (g) ? NO2 (g) + O2 (g) Both the forward and reverse reactions in the equilibrium are elementary bimolecular reactions. What is Kc, for the reverse reaction?

sudhanshu , 12 Years ago
Grade 12
anser 2 Answers
Gaurav
It is given that for the forward reaction is 6.3 × 1014
Then, for the reverse reaction will be, 1/6.3 × 1014 =1.59 x 10-15
Last Activity: 10 Years ago
Subham Patel
Kc=6.3*10^14 at 1000 K
For reverse reaction K =1/Kc
                                        =1/6.3*10^14 =1.59 *10^-15 
Here Temp is given to confuse but it is of no use in this reaction.
Last Activity: 7 Years ago
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