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`        For a reaction SnO2 +2H2 gives rise to 2H2O+Sn at 900 K,at the equilibrium of steam hydrogen mixture, was found to contain 40%H2 by volume. The value of Kp is `
4 months ago

Arun
23811 Points
```							 In the reacn.                 SnO2(s) + 2H2(g) = 2H2O(g) + Sn(l)Since solid and liquid states compounds would not take part in Kc or Kp.Hence, from chemical eqn.,                SnO2(s) + 2H2(g) = 2H2O(g) + Sn(l)                                  t=0        V                 0                                   t=t      V – 2x           2xNow given =>  2x = 0.4(V – 2x)solving we get x = 0.4V/0.8 => V/2Hence Fnal volume becomes,  at t=t               Kc = [(H2O)/(H2)]^2 = > [(2x)/(V-2x)]^2 = > 0.4^2 = > 16/100 = > 0.16. Kp = Kc*(RT)^nn = 3 – 2 = 1Kp = 0.16*0.0821*900 = > 11 (approx.)
```
4 months ago
Vikas TU
10573 Points
```							Dear student Please ollow this link https://www.askiitians.com/forums/Inorganic-Chemistry/for-the-reaction-sno2-s-2h2-g-2h2o-g-sn-l_157581.htmGood Luck
```
4 months ago
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