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For a reaction SnO2 +2Hgives rise to 2H2O+Sn at 900 K,at the equilibrium of steam hydrogen mixture, was found to contain 40%H2 by volume. The value of Kp is
2 months ago

## Answers : (2)

Arun
23523 Points

In the reacn.
SnO2(s) + 2H2(g) = 2H2O(g) + Sn(l)
Since solid and liquid states compounds would not take part in Kc or Kp.
Hence, from chemical eqn.,
SnO2(s) + 2H2(g) = 2H2O(g) + Sn(l)
t=0        V                 0
t=t      V – 2x           2x
Now given =>  2x = 0.4(V – 2x)
solving we get x = 0.4V/0.8 => V/2
Hence Fnal volume becomes,

at t=t               Kc = [(H2O)/(H2)]^2 = > [(2x)/(V-2x)]^2 = > 0.4^2 = > 16/100 = > 0.16.

Kp = Kc*(RT)^n
n = 3 – 2 = 1
Kp = 0.16*0.0821*900 = > 11 (approx.)

2 months ago
Vikas TU
10078 Points
2 months ago
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