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Grade 12Physical Chemistry

For a reaction occuring in an electrochemical cell Kc = 1.3141x 10^307 M^8 and n = 6. If standard reduction potential of cathode is 1.36 V, then what will be the standard oxidation potential of anode ?
(A) 6.32 V (B) 1.66 V (C) 2.71 V (D) 3.16 V

Profile image of mike
9 Years agoGrade 12
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1 Answer

Profile image of Vikas TU
9 Years ago
From Ecell qen. we know thaat,
Ecell = E0cell – (0.0529logK)/n
Putting all the values we get,
0 = E0cell – (0.052log(1.3141x 10^3))/6
E0celll = 0.0270
E0cell => Eocathode – Eoanode  = 0.0270
1.36 – 0.0270 = E0anode
E0anode = 1.33V