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`        For a first order reaction t0.75 is 138.6sec. it`s specific rate constant is (in s^-1)1. 10^-22. 10^-43. 10^-64. 10^-5`
2 years ago

Gopal
54 Points
```							For first order reaction  half life and time required for 75% completion are related as  t0.75=2*t0.5     and specific rate constant is related with half life as  $k=\tfrac{0.693}{t0.5 }$$\therefore$ t0.5=138.6 /2 =69.25 sec$k=\tfrac{0.693}{69.25 }$  ,k=$10 ^{^{-2}}$
```
2 years ago
Ujwal dayma
15 Points
```							T0.75=138.6secT3/4=138.6sec2t1/2=138.6secT1/2=138.6/2secT1/2=69.3As it is a first order reaction so,t1/2=0.693/kTherefore,k=0.693/t1/20.693/69.3=10-2
```
10 months ago
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