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Grade: 12
        
first and second ionization energies of magnesium are 5.7 and 15.035eV the amount of energy in kJ needed to convert all the atoms of magnesium into mg+2 ions present in magnesium vapours is
3 years ago

Answers : (1)

Vikas TU
11143 Points
							
Mg      ------->             Mg+          +  e-      I.E1= 5.7 eV.
Mg+ -------->          Mg2+          +  e-         I.E.2 = 15.035 eV.
For
Mg to Mg2+
the eqns. would be
Mg      ----------->      Mg2+          +     2e-
adding the I.E1 AND IE2 eqns.
We get, the final eqn. therfore
the I.E required for this eqn. would be:    
I.E = I.E1 + I.E2
     = 5.7 + 15.035
     = 20.735 eV.
3 years ago
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