Find the weight by weight percentage of 10 volume of hydrogen peroxide.

H2O2 decomposes slowly on exposure to light 2(H2O2)→2(H20)+02 10vol H202 means 1L of this will give 10L of oxygen (at STP)2(H202). → 02. + H202*34. 22.4L22.4L of 02 is produced fro. 68g of H20210L of 02 will be produced from: 68*10/22.4 =30.35 g/L of. H202Therefore percentage strengthof 10 volume H202 will be: 30.35*10/100 = 3%