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find the number of photons of radiation of frequency 5*10^13 per sec that must be absorbed in order to melt one gm ice when the latent heat of fusion of ice is 330J/g

khushi vijayvargiya , 6 Years ago
Grade 11
anser 2 Answers
Arun

Last Activity: 6 Years ago

1 g requires 33 J , So Total quanta = E = hv = 6.62 x 10-34 x 5x 10^13 = 33.1 x 10^-21 ; 1g of ice will require = 33 / 33.1 x 10^-21 = 1 * 10^21 quanta aprox

User

Last Activity: 6 Years ago

E=n×h×f. n=no.of photons,h=planks constant ,f=frequency. 330=n×6.626×10^-34×5×10^13. n=330×10^34/6.626×5×10^13=9.96×10^21

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