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`        find The mass of CO2, that must be mixed with 20 g of oxygen such that 27 ml of a sample of the resulting mixture would contain equal number of molecules of each gas`
2 years ago

Gopal
54 Points
```							Equal moles contain equal number of particles number of moles of oxygen n =$\tfrac{w}{M}$ = 20/32 =0.625therefore mass of carbondioxide mixed should be =0.625*44 =27.5 gNow ,total volume contain equal number of molecules of oxygen and carbon dioxide.So, any fraction of volume also contain equal number of molecules.
```
2 years ago
Shalini Ravikant Kshirsagar
15 Points
```							CO2 be x gmno.of moles of O2 =given mass ÷molar mass                      =20/32                       =0.625 molNow,for for 0.625 moles of CO2   For 1mol ,44gmso, So,for 0.625 mol ,x gm         X=44*0.625/1         X=27.5 gm
```
6 months ago
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