Arun
Last Activity: 6 Years ago
To find the ionisation energy of a hydrogen like atom with one electron we use the formula
IE = 13.6Z²/n² eV
Where Z is atomic number and n is the shell number.
In this case Z is 3 and n is 1( because hydrogen is having n=1)
So IE Li²+ = 13.6×9 = 122.4 eV.