Grade 9Physical ChemistryFind the Gibbs energy change of the cell at 298K. 3 Cr |Cr3+ (0.1M)|| Cu2+(0.01M) + |Cu. Given E° Cr3+ / Cr = – 0.75V, Cu2+/Cu = +0.34V, F = 96500C. rishav kumar 12 Years agoGrade 9
Sunil Kumar FP11 Years agoCr ------Cr+3 +3e-Cu+2 +2e- ----CuE=E0 +.059/n log(Cu+2/Cr+3)=.34+.75 +.059/6log(.01/.1)=1.09+.059/6log.1 =1.08deltaG=-nFE=-6*96500*1.08=-625.32KJ