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Find the amount of CU deposited at electrode by passing 2 amp electricity in 10 minutes from CUSO4 solution

Shaker , 5 Years ago
Grade 12th pass
anser 1 Answers
Shreyansh Sharma

Last Activity: 5 Years ago

W = ZIt where Z=Eq wt /F , F= 96500C
Eq wt =Molar mass of Cu (63.5)/nfactor
nfactor =2 
Putting all values
63.5×2×10×60/96500×2 = 0.394 g

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