find density of a 3.6M sulpuric acid solution that is 29% h2so4 by mass?
sathwika , 7 Years ago
Grade 11
1 Answers
gaurang gupta
Molarity of acid = 3.6;
Molar mass of H2SO4 = 98g Mass of H2SO4 present in 1 L (1000 mL) of acid = 3.6 x 98 g = 352.8 g Let 'd' be the density of the acid. Density = Mass/Volume Mass of 1000 mL of acid = (d x 1000) g Percentage of H2SO4 in acid = 29 352.9 x 100/1000 d = 29 352.9/10 d = 29 290 d = 352.9 Therefore d = 352.9/290= 1.22 g/mL
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