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Grade: 12
        जटिल यौगिक [Fe (H2O)5 No] SO4 मे अयुग्मित इलेक्ट्रॉनों की संख्या
5 months ago

Answers : (1)

Arun
11589 Points
							

The oxidation state of Fe in [Fe(H2O)5NO]SO4 is +1. Therefore
26Fe+1 = 1s2 2s2 2p6 3s2 3p6 4s1 3d6
When the weak field ligand H2O and strong field ligand NO attack the configuration changes as follows:
26Fe+1 = 1s2 2s2 2p6 3s2 3p6 3d7 4s° 4p° 4d°
The number of unpaired electron in 3d sub-shell is 3.

5 months ago
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