Flag Physical Chemistry> जटिल यौगिक [Fe (H2O)5 No] SO4 मे अयुग्मित...
question mark

जटिल यौगिक [Fe (H2O)5 No] SO4 मे अयुग्मित इलेक्ट्रॉनों की संख्या

Kapil Goswami , 7 Years ago
Grade 12
anser 1 Answers
Arun

The oxidation state of Fe in [Fe(H2O)5NO]SO4 is +1. Therefore
26Fe+1 = 1s2 2s2 2p6 3s2 3p6 4s1 3d6
When the weak field ligand H2O and strong field ligand NO attack the configuration changes as follows:
26Fe+1 = 1s2 2s2 2p6 3s2 3p6 3d7 4s° 4p° 4d°
The number of unpaired electron in 3d sub-shell is 3.

Last Activity: 7 Years ago
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments