explain the nature ofresulting solution when 20 ml of 0.05 M NaOH is mixed with 10 ml of 0.1 N HCL solution at 25 degree celsius. when 10 ml of this solution is diluted 100 times what is the change in ph
SAMBHAV MISHRA , 5 Years ago
Grade 10
1 Answers
Arun
Last Activity: 4 Years ago
0.05 M NaOH = 0.05 N NaOH as number of equivalents = 1 for NaOH
moles of NaOH=0.05 N×20 ml=1 m mole
moles of HCl=0.1 N×10 ml=1 m mole
Number of moles of acid and base are equal thus solution is neutral.
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