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Physical Chemistry

Ethylene glycol is used as an antifreeze in a cold climate. Mass of ethylene glycol whichshould be added to 4 kg of water to prevent it from freezing at –6°C will be: (Kf forwater = 1.86 K kg mol–1, and molar mass of ethylene glycol= 62gmol–1

nikhil

12 Years agoGrade

4 Answers

Sunil Kumar FP

11 Years ago

Let the mass of ethylene glycol be xgm
we have freezing point of water as 0 degreeC
depression in freezing in freezing point=0-(-6)=6degreeC
Now depression in freezing point=Kf*m
m is the molality of the solution
m=(x/62)/4=x/248
we have
6=(1.86*x)/248
=800gm

Aniket Tripathi

8 Years ago

W=6×4000×62÷1000÷1.86=8006=∆t4000=mass of water in gms 62= molecular mass of ethylene glycol1.86= k

Krish Gupta

6 Years ago

gm,xLet the mass of ethylene glycol be

is the molality of the solutionm=(x/62)/4=x/248we have6=(1.86*x)/248=800gmmCNow depression in freezing point=Kf*m⁰ we have freezing point of water as 0 degreeCdepression in freezing in freezing point=0-(-6)=6

Hope it helps.

Kushagra Madhukar

5 Years ago

Dear student,

Please find the answer to your question.

Let the mass of ethylene glycol be xgm

we have freezing point of water as 0^oC

depression in freezing in freezing point=0 – ( – 6) = 6^oC

Now depression in freezing point = K_f*m

m is the molality of the solution

m = (x/62)/4 = x/248

we have

6 = (1.86*x)/248

Hence, x = 248*6/1.86 = 800gm

Thanks and regards,

Kushagra

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