Equivalent weight of H3PO2(molecular weight =m ) when it disproportionates into PH3 and H3PO3

1. M
2. M/2
3. M/4
4. 3M/4

3H3PO2 ------PH3 +2H3PO3
WE have equivalent weight=molecular weight/n factor
for such type of redox reaction the n factor is calculated as
no of electron exchanged/total number of mole used
H3PO2-------PH3
change in oxidation number is from 1 to -3 .Thus 4e- are used
from 2H3PO2 ----2H3PO2
Change in oxidation number is from 1 to +3 therefore electron given is 2e-.for 2 moleculae of H3PO2 thus 4 lectron are used
thus in total 4e- are exchanged
n factor=no of electron/no of mole=4/3
Thus the eq weight=M/(4/3)=3M/4

H 3 PO2 → pH 3 + H 3 PO 3 In first we take h3po2^+1→ph3^-3 thenH3po2^+1→h3po3^+3Mole molecular weight of h 3 PO 2 equals to 3 + 31 + 48 =82 Equivalent weight equals to 82 / 1-(-3)+82/1-3 =82/4+82/2 =61.5

Dear Student,
Please find below the solution to your problem.

3 H3PO2 ------> PH3 + 2 H3PO3
We have equivalent weight = molecular weight/n factor
for such type of redox reaction the n factor is calculated as
no of electron exchanged/total number of mole used
H3PO2 -------> PH3
change in oxidation number is from 1 to -3.
Thus 4e- are used from
2 H3PO2 ----> 2 H3PO2
Change in oxidation number is from 1 to +3
therefore electron given is 2e-.
for 2 moleculae of H3PO2
thus 4 electron are used
thus in total 4e- are exchanged
n factor=no of electron/no of mole
=4/3
Thus the eq weight=M/(4/3)
=3M/4

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