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Grade 11Physical Chemistry

draw orbital diagram of ethene and ethane properly in three marks question

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8 Years agoGrade 11
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ApprovedApproved Tutor Answer1 Year ago

To illustrate the orbital diagrams for ethene (C2H4) and ethane (C2H6), we need to understand the bonding and hybridization that occurs in these molecules. Both compounds consist of carbon and hydrogen atoms, but they differ in their bonding arrangements, which affects their orbital diagrams.

Orbital Diagram of Ethene (C2H4)

Ethene is an example of an alkene, characterized by a double bond between the two carbon atoms. Each carbon atom in ethene undergoes sp2 hybridization, which means one s orbital and two p orbitals combine to form three equivalent sp2 hybrid orbitals. The remaining p orbital on each carbon atom is used to form the double bond.

Steps to Draw the Orbital Diagram for Ethene

  • Step 1: Identify the electron configuration of carbon (C): 1s2 2s2 2p2.
  • Step 2: For sp2 hybridization, the 2s and two 2p orbitals mix to form three sp2 orbitals, which are arranged in a trigonal planar geometry.
  • Step 3: The remaining unhybridized p orbital on each carbon is oriented perpendicular to the plane of the sp2 orbitals.

The orbital diagram for ethene can be represented as follows:

  • Each carbon atom has three sp2 orbitals filled with electrons, forming sigma bonds with hydrogen and the other carbon.
  • The unhybridized p orbitals on each carbon overlap to form a pi bond, completing the double bond between the two carbon atoms.

Orbital Diagram of Ethane (C2H6)

In contrast, ethane is an alkane with single bonds only. Each carbon atom in ethane undergoes sp3 hybridization, which involves one s orbital and three p orbitals combining to form four equivalent sp3 hybrid orbitals.

Steps to Draw the Orbital Diagram for Ethane

  • Step 1: Start with the electron configuration of carbon: 1s2 2s2 2p2.
  • Step 2: For sp3 hybridization, the 2s and three 2p orbitals mix to create four sp3 orbitals, arranged in a tetrahedral geometry.
  • Step 3: Each sp3 orbital is used to form sigma bonds with hydrogen atoms and the other carbon atom.

The orbital diagram for ethane can be summarized as follows:

  • Each carbon atom has four sp3 orbitals filled with electrons, forming sigma bonds with three hydrogen atoms and one carbon atom.
  • There are no unhybridized p orbitals since all orbitals are involved in bonding.

Visual Representation

While I can't draw diagrams directly here, you can visualize ethene as having a double bond between the two carbon atoms, represented by one sigma and one pi bond, while ethane has single bonds represented by sigma bonds only. You can sketch these diagrams based on the descriptions provided, showing the arrangement of orbitals and the bonding between atoms.

In summary, ethene features sp2 hybridization with a double bond, while ethane exhibits sp3 hybridization with only single bonds. Understanding these differences is crucial for grasping the molecular structure and reactivity of these hydrocarbons.