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Grade 12Physical Chemistry

Dihydrogen gas is obtained from natural gas by partial oxidation with steam as per following endothermic reaction: CH4 (g) + H2O (g) = CO (g) + 3H2 (g) (a) Write as expression for Kp for the above reaction. (b) How will the values of Kp and composition of equilibrium mixture be affected

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12 Years agoGrade 12
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ApprovedApproved Tutor Answer1 Year ago

To tackle your question about the equilibrium expression for the reaction of methane with steam to produce carbon monoxide and dihydrogen gas, let’s break it down step by step.

Equilibrium Constant Expression

For the reaction you provided:

CH4 (g) + H2O (g) ⇌ CO (g) + 3H2 (g)

The equilibrium constant expression, Kp, is derived from the partial pressures of the gases involved in the reaction. The general form for Kp is:

Kp = (P_products)^(coefficients) / (P_reactants)^(coefficients)

Applying this to your reaction, we can express Kp as follows:

  • P_CO is the partial pressure of carbon monoxide.
  • P_H2 is the partial pressure of dihydrogen, raised to the power of its coefficient (which is 3 in this case).
  • P_CH4 is the partial pressure of methane.
  • P_H2O is the partial pressure of steam.

Thus, the expression for Kp becomes:

Kp = (P_CO * (P_H2)^3) / (P_CH4 * P_H2O)

Impact of Changes on Kp and Equilibrium Composition

Now, let’s discuss how changes in conditions can affect the value of Kp and the composition of the equilibrium mixture.

Temperature Changes

This reaction is endothermic, meaning it absorbs heat. According to Le Chatelier's principle, if you increase the temperature, the equilibrium will shift to favor the formation of products (CO and H2) to absorb the added heat. Consequently:

  • The value of Kp will increase as the equilibrium shifts to the right.
  • The concentrations of CO and H2 will rise, while those of CH4 and H2O will decrease.

Pressure Changes

When considering pressure, remember that increasing pressure favors the side of the reaction with fewer moles of gas. In this case:

  • The left side has 2 moles of gas (1 CH4 + 1 H2O) and the right side has 4 moles of gas (1 CO + 3 H2).
  • Thus, increasing pressure would shift the equilibrium to the left, resulting in a decrease in Kp.
  • This means that the concentrations of CH4 and H2O would increase, while those of CO and H2 would decrease.

Concentration Changes

If you change the concentration of one of the reactants or products, the system will adjust to counteract that change. For example:

  • Adding more CH4 or H2O will shift the equilibrium to the right, increasing the production of CO and H2.
  • Removing H2 will shift the equilibrium to the left, favoring the formation of H2 from CO and CH4.

In summary, the equilibrium constant Kp is sensitive to temperature changes, while the composition of the equilibrium mixture can be influenced by changes in pressure and concentration. Understanding these principles helps in predicting how a system will respond to various changes, which is crucial in chemical engineering and industrial applications.