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Derive relation between molality and mole fraction
XA = n/N+n and XB = N/N+n XA/XB = n/N = Moles of solute/Moles of solvent = wA/mB/wB×mA XA×1000/XB×mB = wA×1000/wB×mA = m or
XA = n/N+n and XB = N/N+n
XA/XB = n/N = Moles of solute/Moles of solvent = wA/mB/wB×mA
XA×1000/XB×mB = wA×1000/wB×mA = m
or
You went somewhere wrong. The correct relation is(XA x 1000) / [(1-Xa) x mB] = m
Xa= na/na+nb,Xb=nb/na+nbXa/Xb=na/nb=Wa*Ma/Wb*MaXa*1000/Xb*Mb=Wa*1000/Wb*Ma=na*1000/Wb=mXa*1000/(1-Xa)*mb=m
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