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Akanksha Hansika Grade: 11
        
Derive relation between molality and mole fraction
 
2 years ago

Answers : (2)

nishchith
30 Points
										

XA = n/N+n and XB = N/N+n    

 XA/XB = n/N = Moles of solute/Moles of solvent = wA/mB/wB×mA    

XA×1000/XB×mB = wA×1000/wB×mA = m    

or

\small \frac{X_A\times 1000}{1-X_A} = m

2 years ago
Akanksha Hansika
23 Points
										
You went somewhere wrong. The correct relation is
(X1000) / [(1-Xax mB] = m
2 years ago
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