Arun
Last Activity: 7 Years ago
Depression of freezing point∆Tf = Kf × i× m1 molal urea solution freezes at −1.86 oC1.86 = Kf × 1Kf =1.86Using the value of Kf, find the i value∆Tf = Kf × m0.0204 = 1.86 ×i× 0.01i= 1.1CH3COOH ↔CH3COO− + H+C(1−α) Cα Cαi= 1 +αα = 0.1[H+] = Cα = 0.01 × 0.1 = 0.001pH = − log [H+] = − log 0.001 = −log (1 × 10−3) =3