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Grade: 12
        density of air is 0.001293g/cc. its vapour density is ?
6 years ago

Answers : (2)

Sunil Kumar FP
askIITians Faculty
183 Points
							we know thar at stp 22.4lt of everyvgas occupy 1 mole.
1 mole corresponds to its molecular mass
molecular mass=2×vapour density
given density=.001293g/cm^3
1 ml has .001293 gm
22.4 ml has .001293×22.4/10^-3
molecupar mass=28.97
vapour density= mol. mass/2 = 14.485

thanks and regards
sunil kr
askIItian faculty
6 years ago
shahnawaz choudhary
15 Points
							
1 mole = 22.4 litres of any gas 
Now, given :- 0.001293 g/cm3 of air at stp 
Means, we have :- 0.001293 × 22.4/10moles of gas which means molecular weight of gas is 28.96
Now, molecular weight = 2 × vapour denstity 
 So, vapour density = 28.96 /2  which is equal to 
                                   = 14.48 
This types of ques. Are good for jee preparation you can see this ques. In many refrence books and also in many institutional books too.
Thanks
one year ago
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