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```
density of air is 0.001293g/cc. its vapour density is ?
density of air is 0.001293g/cc. its vapour density is ?

```
6 years ago

Sunil Kumar FP
183 Points
```							we know thar at stp 22.4lt of everyvgas occupy 1 mole.1 mole corresponds to its molecular massmolecular mass=2×vapour densitygiven density=.001293g/cm^31 ml has .001293 gm22.4 ml has .001293×22.4/10^-3molecupar mass=28.97vapour density= mol. mass/2 = 14.485thanks and regardssunil kraskIItian faculty
```
6 years ago
shahnawaz choudhary
15 Points
```							1 mole = 22.4 litres of any gas Now, given :- 0.001293 g/cm3 of air at stp Means, we have :- 0.001293 × 22.4/103 moles of gas which means molecular weight of gas is 28.96Now, molecular weight = 2 × vapour denstity  So, vapour density = 28.96 /2  which is equal to                                    = 14.48 This types of ques. Are good for jee preparation you can see this ques. In many refrence books and also in many institutional books too.Thanks
```
2 years ago
618 Points
```							Dear student,Please find the solution to your problem below. We know that at STP 22.4lt of everyvgas occupy 1 mole.1 mole corresponds to its molecular massmolecular mass=2×vapour densitygiven density=.001293g/cm^31 ml has .001293 gm22.4 ml has .001293×22.4/10^-3molecupar mass=28.97vapour density= mol. mass/2 = 14.485 Thanks and regards,Kushagra
```
6 months ago
RISHIKA
550 Points
```							DEAR FRIENDAnswer: The vapour density when the density of air is 0.001293 g/ml is 14.48 gm. At STP or under standard conditions of pressure and temperature, 22.4 l of any gas equals to 1 mole.THANK U
```
6 months ago
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