Grade 12Physical Chemistry
density of air is 0.001293g/cc. its vapour density is ?
4 Answers
Sunil Kumar FP
we know thar at stp 22.4lt of everyvgas occupy 1 mole.
1 mole corresponds to its molecular mass
molecular mass=2×vapour density
given density=.001293g/cm^3
1 ml has .001293 gm
22.4 ml has .001293×22.4/10^-3
molecupar mass=28.97
vapour density= mol. mass/2 = 14.485
thanks and regards
sunil kr
askIItian faculty
shahnawaz choudhary
1 mole = 22.4 litres of any gas
Now, given :- 0.001293 g/cm3 of air at stp
Means, we have :- 0.001293 × 22.4/103 moles of gas which means molecular weight of gas is 28.96
Now, molecular weight = 2 × vapour denstity
So, vapour density = 28.96 /2 which is equal to
= 14.48
This types of ques. Are good for jee preparation you can see this ques. In many refrence books and also in many institutional books too.
Thanks
Kushagra Madhukar
Dear student,
Please find the solution to your problem below.
We know that at STP 22.4lt of everyvgas occupy 1 mole.
1 mole corresponds to its molecular mass
molecular mass=2×vapour density
given density=.001293g/cm^3
1 ml has .001293 gm
22.4 ml has .001293×22.4/10^-3
molecupar mass=28.97
vapour density= mol. mass/2 = 14.485
Thanks and regards,
Kushagra
RISHIKA
DEAR FRIEND
Answer: The vapour density when the density of air is 0.001293 g/ml is 14.48 gm. At STP or under standard conditions of pressure and temperature, 22.4 l of any gas equals to 1 mole.
THANK U
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