Kushagra Madhukar
Last Activity: 4 Years ago
Dear student,
Please find the solution to your problem.
CsCl is BCC structure.
so in BCC structure atoms touch along the body diagonal, which implies that
2(rCs+ + rCl- ) = √3 a
2 x (1.69 + 1.81) = 1.732a
Hence, a = 2 x 3.5/1.732
a = 4.04 Å
Thanks and regards,
Kushagra