Sunil Kumar FP
Last Activity: 10 Years ago
Given that
Length of edge, a = 3.61x10–8 cm
Atomic mass of cupper, M = 63.55 g/mol
Avogadro constant, NA = 6.022x1023 per mol
Number of atoms in unit cell of FCC, Z= 4
Use formula of density
density=Z*M/a^3*Na
=4*63.55/(3.61*10^-8)^3*6.023*10^23
=8.92 g/cm^3