consider a chemical reaction a + b gives a 3 B2 if 6 moles of a and 8 moles of B are initially taken in above reaction and one mole of a3b 2 is formed then left amount of be in above reaction is

To solve this problem, let's go step by step.

Given Data:
Balanced chemical equation:
A + B → A₃B₂
Initial moles:
A = 6 moles
B = 8 moles
Formed moles of A₃B₂ = 1 mole
Step 1: Identify the Stoichiometric Ratios
From the balanced equation, 1 mole of A₃B₂ is formed from:

3 moles of A
2 moles of B
Thus, the mole ratio of A to B in forming A₃B₂ is 3:2.

Step 2: Determine Reactants Consumed
To form 1 mole of A₃B₂, the reaction consumes:

A = 3 moles
B = 2 moles
Step 3: Calculate Remaining Moles
Initially, we had:

A = 6 moles
B = 8 moles
After the reaction:

Remaining A = 6 - 3 = 3 moles
Remaining B = 8 - 2 = 6 moles
Answer:
The remaining amount of B in the reaction is 6 moles.