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`        Components of buffer solution of 0.1 M HCn and 0.2 M Nacn. What is Ph of solution.`
one year ago

## Answers : (2)

Arun
22613 Points
```							The chemical equation for this reaction isHF + NaCN = NaF + HCNHCN is much more weak acid than HF because it's pKa is greaterIf the volumes of HF and NaCN were equal, HF is limiting reagent and is completely transformed into NaF. In the solution there is buffer HCN/CN-, and the pH of this buffer ispH = pKa + lg[A-]/[HA]pH = 9.4 + lg([CN-]/([HCN]) = 9.4 + lg (0.1/0.1) = 9.4Answer: pH = 9.4
```
one year ago
Chhavi Jain
25 Points
```							HCN is a weak acid and CN- is its conjugate base . Therefore , it is an acidic buffer in which HCN is a weak acid and NaCN is providing its conjugate base (CN-). To calculate the pH of an acidic buffer we will use the formula  : pH= pKa + log[conjugate base]/ [acid] pH= pKa + log[ CN-]/ [HCN] using the data pKa of HCN at 25o C  = 9.2 ( not mentioned in the question )pH= 9.2 + log [0.2]/ [0.1] pH= 9.2+ log 2pH= 9.2 + 0.3010 = 9.501 = 9.5 ( approx )
```
one year ago
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