Grade 12Physical Chemistry
claculate n factor of hcl in equationK2Cr2O7 + 14 HCl = 2 KCl + 2 CrCl3 + 2 Cl3 + 7 H2O
claculate n factor of hcl in equation
K2Cr2O7 + 14 HCl = 2 KCl + 2 CrCl3 + 2 Cl3 + 7 H2O
2 Answers
Arun
You should write chemical formula correctly, using caps when required, such as...
Kr2Cr2O7 + HCl ==> KCl + CrCl3 + + Cl2 + H2O and balanced it would be ...
14HCl + K2Cr2O7 → 3Cl2 + 2CrCl3 + 2KCl + 7H2O
and n for HCl is 14
Kr2Cr2O7 + HCl ==> KCl + CrCl3 + + Cl2 + H2O and balanced it would be ...
14HCl + K2Cr2O7 → 3Cl2 + 2CrCl3 + 2KCl + 7H2O
and n for HCl is 14
Shireen Mujawar
In balanced chemical reaction,
14 mole of HCl looses 6 mole of electrons
So,1 mole of HCl looses 6/14 mole of electrons
So, n factor of HCl is 6/14 i.e. 3/7
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