carbon reacts with chlorine form ccl4.36gm of carbon was mixed with 142 g of cl2 . calculate mass of ccl4 produced and the remaining mass of reactant.

To determine the mass of carbon tetrachloride (CCl4) produced from the reaction between carbon and chlorine, we first need to understand the chemical reaction involved. The balanced equation for the reaction is:

C + 2Cl2 → CCl4

This equation tells us that one mole of carbon reacts with two moles of chlorine gas to produce one mole of carbon tetrachloride. Now, let’s break down the calculations step by step.

Step 1: Calculate Moles of Reactants

First, we need to find out how many moles of carbon and chlorine we have. The molar mass of carbon (C) is approximately 12 g/mol, and the molar mass of chlorine (Cl2) is about 71 g/mol (since Cl is approximately 35.5 g/mol, and there are two chlorine atoms in the molecule).

• Moles of Carbon:

  Using the formula: Moles = Mass / Molar Mass

  Moles of C = 36 g / 12 g/mol = 3 moles

• Moles of Chlorine:

  Moles of Cl2 = 142 g / 71 g/mol = 2 moles

Step 2: Determine the Limiting Reactant

Next, we need to identify the limiting reactant, which is the reactant that will be completely consumed first and thus limits the amount of product formed. According to the balanced equation, 1 mole of carbon reacts with 2 moles of chlorine.

• From our calculations, we have:
• 3 moles of carbon
• 2 moles of chlorine

To react completely with 2 moles of chlorine, we would need 1 mole of carbon. Since we have 3 moles of carbon, and only 2 moles of chlorine, chlorine is the limiting reactant.

Step 3: Calculate the Mass of CCl4 Produced

Since chlorine is the limiting reactant, we can now calculate how much CCl4 is produced. According to the balanced equation, 2 moles of Cl2 produce 1 mole of CCl4. Therefore, 2 moles of Cl2 will produce:

• 1 mole of CCl4

Now, we need to find the mass of CCl4 produced. The molar mass of CCl4 is:

• 1 (C) = 12 g/mol
• 4 (Cl) = 4 x 35.5 g/mol = 142 g/mol
• Total = 12 g/mol + 142 g/mol = 154 g/mol

Since we produced 1 mole of CCl4, the mass of CCl4 produced is:

Mass of CCl4 = 1 mole x 154 g/mol = 154 g

Step 4: Calculate Remaining Mass of Reactants

Now, let’s find out how much of the reactants remain after the reaction. We started with:

• 36 g of carbon
• 142 g of chlorine

Since chlorine is the limiting reactant and it was completely consumed, we have:

Remaining mass of Cl2 = 0 g

For carbon, we used 1 mole (12 g) to react with 2 moles of chlorine. Therefore, the remaining mass of carbon is:

Remaining mass of C = 36 g - 12 g = 24 g

Summary of Results

• Mass of CCl4 produced: 154 g
• Remaining mass of carbon: 24 g
• Remaining mass of chlorine: 0 g

In conclusion, from the reaction of 36 g of carbon with 142 g of chlorine, we produced 154 g of carbon tetrachloride, and there are 24 g of carbon left unreacted, while all the chlorine has been consumed.