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Grade 11Physical Chemistry

calcutta the weight of CaCO3 required to prepare C2H2,which is required to prepare 1 mole of benzene

Profile image of philip
7 Years agoGrade 11
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1 Answer

Profile image of Rajat
7 Years ago
3(C2H2) (at 873 k) ----> C6H6
1 mole of CaCO3 is required to make 1 mole of CaC2 which in turn upon reacting with water forms 1 mole of C2H2.
So 3 mole of CaCO3 is required to make 1 mole benzene. 
3 mole CaCO3 = 3(40+12+48) = 300g
 
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