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Grade 11Physical Chemistry

calculate transition in helium lithium and berillyum which have same wavelength as transition n=2 to n=1 in hydrogen atom

Profile image of aishwarya
7 Years agoGrade 11
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2 Answers

Profile image of Ravleen Kaur
7 Years ago
560-1472_1.PNG

In this formula,
Use
z=2
n2=2
n2=1
Profile image of Khimraj
7 Years ago
For He+ ion, we have
1/λ = Z2R­H [1/n12 -1/n22]
= (2)2RH [1/(2)2 – 1/(4)2] = RH 3/4 ….(i)
Now for hydrogen atom 1/λ = RH [1/n12 -1/n22] ….(ii)
Equating equation (i) and (ii), we get
1/n12 -1/n22 = 3/4
Obviously, n1 = 1 and n2 = 2
Hence, the transition n = 2 to n = 1 in hydrogen atom will have the same wavelength as the transition, n = 4 to n = 2 in He+ species.