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Calculate the wavelength in Angstrom of the photon that is emitted when an electron in the Bohr orbit, n = 2 returns to the orbit, n = 1 in the hydrogen atom. The ionization potential of the ground state hydrogen atom is 2.17 * 10-11 erg per atom.

Shane Macguire , 10 Years ago
Grade upto college level
anser 1 Answers
Deepak Patra

Last Activity: 10 Years ago

(i) Energy of nth orbit En = E1/n2
(ii) Difference in energy = E1 – E2 = hv = hc/λ or λ = hc/E1 – E2
Given E1 = 2.17 * 10-11
∴ Energy of second orbit = E2 = 2.17 *10-11/22 = 0.5425 *10-11 erg
∆ = E1 – E2 = 2.17 * 10-11 – 0.5425 * 10-11 = 1.0275 * 10-11 erg
λ = 6.62 *10-27 *3 *1010/1.6275 *10-11 = 12.20 * 10-6 cm = 1220 Å

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