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Volume v of air is 1000km3=1*10^12 m3.
Standard temperature, T=273.15K
Standard pressure P is 101325Pa.
0.076g of Xe will have (0.076/131.29) moles=5.789*10^-5.
The volume of 0.076g of xe is 7.6*10^-5/5.761=1.319*10^-5
Volume of Xe in 1000km3 is given by;
P/TRn=VV=nRT/P
V= (5.789*10^-4) *8.314* 273.15/101325
v =1.297*10^-5m3
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