calculate the radius of gyration of a hoop of radius 5 centimetre rotating about an Axis passing through its centre and normal to its plane

The radius of gyration of a hoop of  radius 5.00 cm rotating about an axis passing through its centre and normal to its plane.
I(tangent) = 2/5 Ma² + MR²
∴  I(tangent) = 7/5 MR²
∴ Mk² = 7/5 MR²
∴ k = √(7/5 x 5² = √35 cm

 

Dear student 
The radius of gyration of hoop of Radius 5.00cm rotating about an axis passing through its centre and normal to its plane 
I(tangent) = 2/5 Ma^2 + MR^2 
MK^2 = 7/5 MR^2 
K^2 = 7/5 R^2 
k = sqrt(35) 
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