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Grade: 11
        
calculate the radius of gyration of a hoop of radius 5 centimetre rotating about an Axis passing through its centre and normal to its plane
4 months ago

Answers : (2)

Arun
24426 Points
							
The radius of gyration of a hoop of  radius 5.00 cm rotating about an axis passing through its centre and normal to its plane.
I(tangent) = 2/5 Ma² + MR²
∴  I(tangent) = 7/5 MR²
∴ Mk² = 7/5 MR²
∴ k = √(7/5 x 5² = √35 cm
 
4 months ago
Vikas TU
11142 Points
							
Dear student 
The radius of gyration of hoop of Radius 5.00cm rotating about an axis passing through its centre and normal to its plane 
I(tangent) = 2/5 Ma^2 + MR^2 
MK^2 = 7/5 MR^2 
K^2 = 7/5 R^2 
k = sqrt(35) 
Hope this information will clear your doubts about the topic .
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible 
4 months ago
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