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Grade 12Physical Chemistry

calculate the ph of the solution obtained by mixing 200 ml of soln with ph=4 and 400 ml of soln with ph=5

Profile image of Utsav Bhandari
8 Years agoGrade 12
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1 Answer

Profile image of Piyush Upadhyay
8 Years ago
Dear student as we can see both of the given solutions are acidic in nature so [H+] = 10^-5 and 10^-4 mole/lit. Now normality = [H+], So by applying normality equation I.e. Nr= (N1V1+N2V2)/(V1+V2) we get Nr 7*10^-5.Taking -log both sides we get -log(7*10^-5) and that is equal to 4.15 hope it helps. Please approve it 😊😊