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`        Calculate the pH of solution formed on mixing 0.2 M NH4Cl  & 0.1 M NH3 .The pOH of ammonia solution is 4.75.?`
2 years ago

## Answers : (1)

Arun
23340 Points
```							Dear SandippOH = pKb + log ([salt]/[base])pKb = 4.75[salt] = 0.2M[base] = 0.1MSubstitute into equation:pOH = 4.75 + log (0.2/0.1)pOH = 4.75 + log 2pOH = 4.75 + 0.30pOH = 5.05pH = 14.00-pOHpH = 14.00-5.05pH = 8.95 RegardsArun (askIITians forum expert)
```
2 years ago
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