Grade 11Physical Chemistry
Calculate the pH of a mixture containing 50ml of 1(N) HCl and 30 ml 1(N) NaOH .((Ans.. 0.6)).
Calculate the pH of a mixture containing 50ml of 1(N) HCl and 30 ml 1(N) NaOH .((Ans.. 0.6)).
2 Answers
Rohan Gujar
Approved Tutor Answer7 Years agoJust use formula [H+]=(M1V1+M2V2)/(V1+V2)
So, [H+]=(50-30)/80. [N=M×n-factor]
[H+]=0.25. So pH= -log[H+]
= -log(0.25)=0.6 Ans.
Arun
Approved Tutor Answer7 Years agoDear student
Mole = concentration x volume
mole of NaOH = 30ml x 1 = 30.0
mole of HCl = 50ml x 1= 50.0
30 mole of NaOH exactly neutralized by 30 mole of HCl.
NaOH + HCl = NaCl + H2O
that is 50 -30 = 20 HCl mole
Con of H+ = no of mole of H+ / total volume of solution (50+ 30 ml = 80 ml)
= 20/80 = 0.25
pH = - log ( H+)
= - log (1/4) = 0.6021
s0 the pH of solution will be 0.6021
Regards
Arun
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