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calculate the PH of 20 ml 0.25M CH3COOH and 50ml 0.1M NaOH solution

Tanusri Bose , 6 Years ago
Grade
anser 1 Answers
Arun

Last Activity: 6 Years ago

  • The answer is simple.
  • pH= pKa+ log (salt/acid).
  • In the mixture, No.of m.moles of acetic acid=20 x0.25= 5 m moles.
  • The no.of m moles of NaOH =50x0.1= 5 m.moles.
  • So log (salt/acid)= (log1/0) =0
  • So pH= pKa= 4.74
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