Calculate the overall complex dissociation equilibrium constant for the Cu(NH3)42+ ion, given that ß4 for this complex is 2.1 × 1013

Question

Sunil Kumar FP · Answer

the overall complex dissociation equilibrium constant for the Cu(NH3)42+ ion the overall dissociation constant is the reciprocal of overall stability constant i,e 1/beta =1/2.1*10^13 =4.7 *10^-14

Kushagra Madhukar · Answer

Dear student, Please find the answer to your question. The overall complex dissociation equilibrium constant for the Cu(NH 3 ) 4 2+ ion The overall dissociation constant is the reciprocal of overall stability constant i,e 1/beta =1/2.1 x 10 13 =4.7 x 10 -14 Thanks and regards, Kushagra

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Calculate the overall complex dissociation equilibrium constant for the Cu(NH3)42+ ion, given that ß4 for this complex is 2.1 × 1013

Calculate the overall complex dissociation equilibrium constant for the Cu(NH3)42+ ion, given that ß4 for this complex is 2.1 × 1013

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