0

Guest

Courses New

Calculate the overall complex dissociation equilibrium constant for the Cu(NH3)42+ ion, given that ß4 for this complex is 2.1 × 1013

Calculate the overall complex dissociation equilibrium constant for the Cu(NH3)42+ ion, given that ß4 for this complex is 2.1 × 1013

Grade:9

2 Answers

Sunil Kumar FP
askIITians Faculty 183 Points
9 years ago
the overall complex dissociation equilibrium constant for the Cu(NH3)42+ ion
the overall dissociation constant is the reciprocal of overall stability constant i,e 1/beta
=1/2.1*10^13 =4.7 *10^-14
Kushagra Madhukar
askIITians Faculty 628 Points
3 years ago
Dear student,
Please find the answer to your question.
 
The overall complex dissociation equilibrium constant for the Cu(NH3)42+ ion
The overall dissociation constant is the reciprocal of overall stability constant i,e 1/beta =1/2.1 x 1013 =4.7 x 10-14
 
Thanks and regards,
Kushagra
 

Think You Can Provide A Better Answer ?

Other Related Questions on Physical Chemistry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More