Calculate the order of the reaction for which the rate becomes half if the volume of the container is doubled having the same amount of the reactant. Hints (assuming all the reactant & product are in gaseous state)
Smrutirekhapanda
9 Years agoGrade 12th pass
1 Answer
Aayush Baliyan
9 Years ago
Since by doubling up the volume the rate of reaction is becoming half of the initial value having the same amount of the reactant so it is clear that the order of the reaction is 1/2