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Calculate the number of unpaired electrons in the following gaseous ions: Mn3+, Cr3+, V3+ and Ti3+. Which one of these is the most stable in aqueous solution?

Calculate the number of unpaired electrons in the following gaseous ions: Mn3+, Cr3+, V3+ and Ti3+. Which one of these is the most stable in aqueous solution?

Grade:9

1 Answers

Sunil Kumar FP
askIITians Faculty 183 Points
9 years ago
number of unpaired electrons in the following gaseous ions:
Mn+3 =4
Cr+3 =3
V+3 =2
Ti+3=1
out of these Cr+3 is most stable in aqueous solution because it has t^3 2g configuration.

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