Grade 9Physical ChemistryCalculate the number of the constituents atom in 53g of Na2CO3 PrathMesh lande 9 Years agoGrade 9
Me9 Years agoGiven mass=53gMolar mass of Na2CO3 = 23×2+12+48 = 46+60= 106gNo. Of moles = given mass /molar mass = 53/106 =0.5Now 1 mole = 6.02×10^23 atomsSo, 0.5 moles = 0.5×6.02×10^23. = 3.010×10^23 atoms